2x^2+3x+6=180

Solution for 2x^2+3x+6=180 equation:

2x^2+3x+6=180

We move all terms to the left:

2x^2+3x+6-(180)=0

We add all the numbers together, and all the variables

2x^2+3x-174=0

a = 2; b = 3; c = -174;
Δ = b2-4ac
Δ = 32-4·2·(-174)
Δ = 1401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1401}}{2*2}=\frac{-3-\sqrt{1401}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1401}}{2*2}=\frac{-3+\sqrt{1401}}{4}
$